4/3(x^2-4)^(-1/3)

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Solution for 4/3(x^2-4)^(-1/3) equation: 


D( x )

x^2-4 = 0

x^2-4 = 0

x^2-4 = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x in (-oo:-2) U (-2:2) U (2:+oo)

(4/3)*(x^2-4)^(-1/3) = 0

4/3/((x^2-4)^(1/3)) = 0

4/3 = 0

x belongs to the empty set

x belongs to the empty set

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